> 알고리즘 문제 풀이/BOJ
4195-친구 네트워크 (python)
bky373
2020. 10. 12. 17:25
def find(x):
if x != parents[x]:
parents[x] = find(parents[x])
return parents[x]
def union(x, y):
root1 = find(x)
root2 = find(y)
if root1 != root2:
parents[root2] = root1
numbers[root1] += numbers[root2]
tc = int(input())
for _ in range(tc):
parents = dict()
numbers = dict()
f = int(input())
for _ in range(f):
x, y = input().split()
if x not in parents:
parents[x] = x
numbers[x] = 1
if y not in parents:
parents[y] = y
numbers[y] = 1
union(x, y)
print(numbers[find(x)])